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\title{TD Maths discrètes}
\author{William Hergès\thanks{Sorbonne Université}}

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	\maketitle
    \section*{Exercice 1}
    $(0,0)$, $(0,1)$, $(0,2)$, $(1,2)$, $(2,2)$

    $n$ tq $(n,n)$ est dans $\mathrm{Inf}_1$.
    Donc $(n+1,n+1)$ est dans $\mathrm{Inf}_1$.
    \section*{Exercice 2}
    $u$ et $v$ dans $L$.
    $$ w = a.u.v $$
    $$ |w|_a = 1+|u|_a+|v|_b = |u|_b + |v|_b - 1 $$
    $$ |w|_b = |u|_b + |v|_b $$
    Donc 
    $$ |w|_a + 1 = |w_b| $$
    \section*{Exercice 3}
    $$ h(\{t,a,b\}) = \left\{\begin{matrix}h(\varepsilon) = 0\\ h(\{t, a, b\}) = 1 + \max\{h(a),h(b)\}\end{matrix}\right. $$
    $$ n(\{t,a,b\}) = \left\{\begin{matrix}h(\varepsilon) = 0\\ h(\{t, a, b\}) = 1 + n(a)+n(b)\end{matrix}\right. $$
    $$ ar(\{t,a,b\}) = \max\{0,h(\{t,a,b\})-1\} $$
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